m²-1分之m²-2m+1÷(m+1分之m-1-1+m)

m²-1分之m²-2m+1÷(m+1分之m-1-1+m)
m²-1分之m²-2m+1÷(m+1分之m-1-1+m)

m²-1分之m²-2m+1÷(m+1分之m-1-1+m)
原式=(m-1)²/(m+1)(m-1)÷[(m-1)-(m+1)²]/(m+1)
=(m-1)/(m+1)×(m+1)/(-m²-m-2)
=-(m-1)/(m²+m+2)

=(m-1)²/(m+1)(m-1) ÷[(m-1)+(m+1)(m-1)]/(m+1)
=(m-1)/(m+1)×(m+1)/m(m-1)
=1/m

您好

答题不易，望采纳O(∩_∩)O谢谢 

m²-1分之m²-2m+1÷(m+1分之m-1-1+m)
=(m-1)²/(m+1)(m-1)÷[(m-1)-(m+1)²]/(m+1)=(m-1)/(m+1)×(m+1)/(-m²-m-2)=-(m-1)/(m²+m+2)
满意请采纳，谢谢！【姜永哲11】