(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2

(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2
(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2

(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2
(1/a+1/b)除以a^2+2ab+b^2/a+b
=（a+b）/ab÷（a+b）^2/(a+b)
=1/ab
=1/(-3x2)
=-1/6

答案是－1/42