1.x²-1=(x-1)(x+1) ∴x²-1/x+1=________2.x³-1=(x-1)(x²+x+1) ∴x³-1/x²+x+1=_________3.xˇ4-1=(x-1( )∴xˇ4-1/xˇ3+x²+x+1=x-14.猜想:xˇn-1=(x-1)( ),∴xˇn-1/( )=x-1如果要计

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1.x²-1=(x-1)(x+1) ∴x²-1/x+1=________2.x³-1=(x-1)(x²+x+1) ∴x³-1/x²+x+1=_________3.xˇ4-1=(x-1( )∴xˇ4-1/xˇ3+x²+x+1=x-14.猜想:xˇn-1=(x-1)( ),∴xˇn-1/( )=x-1如果要计

1.x²-1=(x-1)(x+1) ∴x²-1/x+1=________2.x³-1=(x-1)(x²+x+1) ∴x³-1/x²+x+1=_________3.xˇ4-1=(x-1( )∴xˇ4-1/xˇ3+x²+x+1=x-14.猜想:xˇn-1=(x-1)( ),∴xˇn-1/( )=x-1如果要计
1.x²-1=(x-1)(x+1) ∴x²-1/x+1=________
2.x³-1=(x-1)(x²+x+1) ∴x³-1/x²+x+1=_________
3.xˇ4-1=(x-1( )∴xˇ4-1/xˇ3+x²+x+1=x-1
4.猜想:xˇn-1=(x-1)( ),∴xˇn-1/( )=x-1
如果要计算2ˇ10+2ˇ9+······+1的值,你能用一个两项式表达2ˇ10+2ˇ9+······+1的值吗?

1.x²-1=(x-1)(x+1) ∴x²-1/x+1=________2.x³-1=(x-1)(x²+x+1) ∴x³-1/x²+x+1=_________3.xˇ4-1=(x-1( )∴xˇ4-1/xˇ3+x²+x+1=x-14.猜想:xˇn-1=(x-1)( ),∴xˇn-1/( )=x-1如果要计
1.x-1
2.x-1
3.x的三次+x²+x+1
4.(x的n次+x的n-1次+……+1)
(x的n次+x的n-1次+……+1)
5.2ˇ10+2ˇ9+······+1
=3
2ˇ10+2ˇ9+······+1
=(2-1)(2的10次+2的9次+……+1)