1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证

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1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证

1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证
1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证

1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证
这里用到:(sin)^2+(cosx)^2=1,
原式=(cosx-sinx)^2/(cosx+sinx)(cosx-sinx)
=(cosx-sinx)/(cosx+sinx)
=(1-tanx)/(1+tanx).