(1/3*5+1/5*7+.+1/1997*1999

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(1/3*5+1/5*7+.+1/1997*1999

(1/3*5+1/5*7+.+1/1997*1999
(1/3*5+1/5*7+.+1/1997*1999

(1/3*5+1/5*7+.+1/1997*1999
1/(2n+1)(2n+3)=1/2[1/(2n+1) - 1/(2n+3)]
1/3*5+1/5*7+.+1/1997*1999
=1/2(1/3-1/5+1/5-1/7+……1/1997-1/1999)
=1/2(1/3-1/1999)
=998/5997

因为
1/3*5=1/2*(1/3-1/5)
1/5*7=1/2*(1/5-1/7)
.
.
.
1/1995*1997=1/2*(1/1995-1/1997)
所以
1/3*5+1/5*7+......+1/1997*1999
=1/2(1/3-1/5+1/5-1/7+......+1/1997-1/1999)
=1/2*(1/3-1/1997)
=2/5997

因为1/(2n+1)(2n+3)=(1/2)*(1/(2n+1)-1/(2n+3))
所以1/3*5=(1/2)*(1/3-1/5)
1/5*7=(1/2)*(1/5-1/7)
......
1/1997*1999=(1/2)*(1/1997-1/1999)
1/3*5+1/5*7+......+1/1997*1999=1/2*(1/3-1/5+1/5-1/7+......+1/1997-1/1999)=1/2*(1/3-1/1999)=998/5997