作业帮[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 00:58:10
![[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]](/uploads/image/z/387594-18-4.jpg?t=%5B%281%2B2%5E-%281%2F32%29%5D%2A%5B%281%2B2%5E-%281%2F16%29%5D%2A%5B%281%2B2%5E-%281%2F8%29%5D%2A%5B%281%2B2%5E-%281%2F4%29%5D%2A%5B%281%2B2%5E-%281%2F2%29%5D)
[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
=[(1-2^-(1/32)]*[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]/[(1-2^-(1/32)]
=[1-2^(-1)]/[(1-2^-(1/32)]
=1/[(2-2^(31/32)]