lim(n/(n^2+1)+...+n/(n^2+n))x趋向于无穷 求解答过程~

lim(n+3)(4-n)/(n-1)(3-2n) lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 lim(2^n+3^n)^1 (n趋向无穷) lim(n^3+n)/(n^4-3n^2+1) lim(1-1/n)^(n^2)=? lim(1-1/n^2)^n=? lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞ lim（n→∞) （(2n!/n!*n)^1/n的极限用定积分求是lim（n→∞) 1/n(2n!/n!)^1/n 不好意思 lim n->无穷大(2^n-1)/(3^n+1) lim (1+1/2n)^n n趋向于无穷大 lim n->∞{2/((1+ 1/n )^n)}=? lim(1+1/(n+2))^n其中n趋近无穷 lim根号n^2+n+1/3n-2 lim根号n^2+n+1/3n-2=? lim (2n-1)/(2^n)=?n=>无穷大 求极限n~∞,lim(n+1)/2n lim(根号(n平方+2n)-根号(n平方-1)) 求lim n→∞ (1+2/n)^n+3