f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 18:42:43
f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c

f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c

f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
y'=3ax^2+2bx+c
将x=-1,y'=0代入得方程1 3a-2b+c=0
将x=3代入,得方程2 k=y'=27a+6b+c=-8
将x=3,y=-24代入得方程3 27a+9b+3c=-24
解这三个方程可得a,b,c