{x-5}分之{x-4} --{x-6}分之{x-5} ={x-8}分之{x-7} --{x-9}分之{x-8} ,解这个方程

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{x-5}分之{x-4} --{x-6}分之{x-5} ={x-8}分之{x-7} --{x-9}分之{x-8} ,解这个方程

{x-5}分之{x-4} --{x-6}分之{x-5} ={x-8}分之{x-7} --{x-9}分之{x-8} ,解这个方程
{x-5}分之{x-4} --{x-6}分之{x-5} ={x-8}分之{x-7} --{x-9}分之{x-8} ,解这个方程

{x-5}分之{x-4} --{x-6}分之{x-5} ={x-8}分之{x-7} --{x-9}分之{x-8} ,解这个方程
由(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)/(x-9) 得:(X-4)/(X-5)-(X-7)/(X-8)=(X-5)/(X-6)-(X-8)/(X-9) 即:【1+1/(x-5) 】-【1+1/(x-8)】=【1+1/(x-6)]】-【1+1/(x-9)】 1/(x-5)-1/(x-8)=1/(x-6)-1/(x-9) 通分得:-3/(X-5)(X-8)=-3/(X-6)(X-9) 所以(X-5)(X-8)=(X-6)(X-9) 即x^2-13x+40=x^2-15x+54 2x=14 x=7,经检验x=7 是原方程的解,所以原方程的解是x=7

(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)/(x-9) [1 + 1/(x-5)] - [1 + 1/(x-6)] = [1 + 1/(x-8)] - [1 + 1/(x-9)] 1/(x-5) + 1/(x-9) = 1/(x-8) + 1/(x-6) (通分) [(x-9) + (x-5)]/[(x-5)(x-9)] = [x -6 + (x...

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(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)/(x-9) [1 + 1/(x-5)] - [1 + 1/(x-6)] = [1 + 1/(x-8)] - [1 + 1/(x-9)] 1/(x-5) + 1/(x-9) = 1/(x-8) + 1/(x-6) (通分) [(x-9) + (x-5)]/[(x-5)(x-9)] = [x -6 + (x-8)]/[(x-6)(x-8)] (2x-14)/(x-14x+45) = (2x-14)/(x-14x+48) (对角相乘) (2x-14)(x-14x+48) = (2x-14)(x-12x+45) (2x-14)(x-14x+48 - x + 14x - 35) = 0 (2x-14)(3)=0 x = 7 x = 6

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