(2m+n-p)乘(2m-n+p)=()
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(2m+n-p)乘(2m-n+p)=()
(2m+n-p)乘(2m-n+p)=()
(2m+n-p)乘(2m-n+p)=()
(2m+n-p)×(2m-n+p)
=[2m+(n-p)]×[2m-(n-p)]
=(2m)²-(n-p)²
=4m²-(n²-2np+p²)
=4m²-n²+2np-p²
首先把n-p和n+p 看成一个整体 原式=[ 2m+(n-p)]乘[2m-(n-p)] (根据平方差公式得) =4m^2-(n-p)^2
(2m+n-p)乘(2m-n+p)=()
m-(2m-n-p)=
(2m+n-p)( 2m+p-n)
若 P=2m,m=2n,则m+p-n等于()
已知有理数m,n,p,q在数轴上的位置如图所示,且|m|=|n| ,化简(1)|m+n|+|m+p|+|q+p|(2)|n-m|--3|m+p|-|-n-q|+|q-p|
(2m+n-p)(2m-n+p)==?
(m+n)-( )=2m-p
(m+n-p)^2 等于多少?
n-m的三次方的p次方乘m-n乘n-m的p次方的四次方[(n-m)³]的p次方×[(m-n)×(n-m)的p次方]的四次方
(m-2n-p)(m-2n+p)-(m+2n+p)(m+2n+p)
因式分解(m+n)(p+q)-(n-m)(p-q)
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