已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值

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已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值

已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值
已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值

已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值
由x^2-8x+y^2-y+16又1/4=0可知
(x-4)^2+(y-0.5)^2=0,解得
x=4,y=0.5
利用平方差公式及完全平方公式化简
[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y=y-x
代入数据,得 原式=3.5