1/(sin^4xcos^4x)的不定积分
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 11:40:25
1/(sin^4xcos^4x)的不定积分
1/(sin^4xcos^4x)的不定积分
1/(sin^4xcos^4x)的不定积分
∫1/(sin^4xcos^4x)dx
=∫16/sin^4(2x)dx
=∫16csc^4(2x)dx
=∫16[cot^(2x)+1]csc^2(2x)dx
=-∫8[cot^2(2x)+1]dcot(2x)
=-8/3cot^3(2x)-8cot(2x)+C
1/(sin^4 xcos^4 x)积分
1/(sin^4xcos^4x)的不定积分
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
求sin^4x+cos^4x=1-2sin^2xcos^2x的详细答案!
y=1-4sin²xcos²x的导数y'=
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
SIN^4XCOS^4XD的不定积分
求证sin^4x+cos^4x=1-2sin^2xcos^2x
sin^4x+cos^4x=1-2sin^2Xcos^2X谢谢额
求证 sinˇ4X+sin²Xcos²X+cos²X = 1
sin^4+sin^2xcos^2x+cos^2x 证明 =1
sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简)
1-2sin xcos x/cos的平方x
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos^2x+cos^4x 是根据什么化简的?
求证 cos*xcos*y + sin*xsin*y + sin*xcos*y + xin*ycos*x = 1cos*xcos*y + sin*xsin*y + sin*xcos*y + sin*ycos*x = 1注意:[*] 的意思是 [ ^2 ]写下左右过程..
已知函数f(x)=sin xcos x+sin x/cos x+3,若f(lg a)=4,则f(lg 1/a)的值为________.