作业帮求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x
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求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x
求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta
求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x
求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x
原式=sin^2 x/(sinx-cosx)-(sinx+cosx)/(sin^2 x/cos^2 x-1)=sin^2 x/(sinx-cosx)-(sinx+cosx)*cos^2 x/(sin^2 x-cos^2 x)=(sin^2 x-cos^2 x)/(sinx-cosx)=sinx+cosx
t^2 - 1 = (s^2 - c^2) / c^2 = (s+c)(s-c) / c^2
LEFT = s^2 / (s-c) - (s+c) / ((s+c)(s-c) / c^2) = s^2 / (s-c) - c^2 / (s-c) = (s^2-c^2) / (s-c) = s+c = RIGHT
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(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1